Domain dan Kodomain

f(x) = 3 – 2x

a.

x = -1

f(-1) = 3 – 2(-1)

f(-1) = 3 + 2

f(-1) = 5

b.

f(a) = -1

3 – 2a = -1

2a = 3 + 1

a = 4/2

a = 2

c.

domain P = {-3, -2, -1, 0, 1, 2, 3}

kodomain Q = { x|x bilangan asli}

f(P) = Range

f(-3) = 3 – 2(-3) = 9

f(-2) = 3 – 2(-2) = 7

f(-1) = 3 – 2(-1) = 5

f(0) = 3 – 2.0 = 3

f(1) = 3 – 2.1 = 1

f(2) = 3 – 2.2 = -1

f(3) = 3 – 2.3 = -3

Range fungsi

= {-3, -1, 1, 3, 5, 7, 9}